Subject: VIN decode stuff
Date: Sun, 20 Jun 1999 14:52:27 -0400 (EDT)
From: zcwp11@ACCESS.ETSU.EDU
Reply-To: oldsgmail@MailingList.net
To: oldsgmail@MailingList.net, oldsmobile@chebucto.ns.ca
Found this on the net earlier... didn't know this... probably make a good
addition for the FAQ.
Peace, Goodwill, and Happy Oldsmobilling,
Clayton Pierce,
zcwp11@Access.ETSU.edu
1979 Cutlass Supreme (260, 2bbl, THM200, 205k miles)
To determine check digit (9th digit) of your car you need to take the VIN
and assign any letters in the VIN with a set value (number) as follows:
A = 1, B = 2, C = 3, D = 4, E = 5, F = 6, G = 7, H = 8,
J = 1, K = 2, L = 3, M = 4, N = 5, O = 6, P = 7, R = 9,
S = 2, T = 3, U = 4, V = 5, W = 6, X = 7, Y = 8, Z = 9
Any numbers in the VIN remain the same (not replaced) and thus you have a
17 digit number.
Then you must multiply each of the 17 digits by a set "weight"
(multiplier). The weight applied to each digit is as follows:
1st = 8, 2nd = 7, 3rd = 6, 4th = 5, 5th = 4, 6th = 3, 7th = 2, 8th = 10,
9th = 0 (check digit), 10th = 9, 11th = 8, 12th = 7, 13th = 6, 14th = 5,
15th = 4, 16th = 3, 17th = 2
After multiplying each VIN digit by the associated weight - add up the
results of all 17 products. Then divide by 11 and the remainder is your
check digit.
If the remained is 10, then the check digit is 'X'.
Here's an example: VIN = 1G1BL52P7TR115520 (note '7' is the check digit)
VIN 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0
Assigned Values 1 7 1 2 3 5 2 7 7 3 9 1 1 5 5 2 0
Multiplier 8 7 6 5 4 3 2 10 0 9 8 7 6 5 4 3 2
Add the products: (1 X 8) + (7 X 7) + (1 X 6) ... (0 X 2) = 337
Divide 337 by 11 which gives you 30, and a remainder of 7 which is the same
as the 9th digit of the VIN.
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